双语化学辞典Chem Lexicon
高中Senior high 分子光谱与结构测定 Molecular spectroscopy & structure determination

朗伯–比尔定律Beer–Lambert law

\[A = \lg\frac{I_0}{I} = -\lg T = \varepsilon\, b\, c\]
透射率与多组分加和transmittance and additivity for mixtures
\[T = \frac{I}{I_0} = 10^{-\varepsilon bc},\qquad A_\text{总} = \sum_i \varepsilon_i b c_i\]\[T = \frac{I}{I_0} = 10^{-\varepsilon bc},\qquad A_\text{total} = \sum_i \varepsilon_i b c_i\]

含义Meaning

单色光通过稀溶液时,吸光度与吸光物质浓度和光程成正比。分光光度法定量分析的基础。

For monochromatic light through a dilute solution, absorbance is proportional to concentration and path length — the basis of spectrophotometric analysis.

符号说明Symbols

符号Symbol含义 Meaning单位 Unit
\(A\)吸光度absorbance1
\(T\)透射率transmittance1
\(\varepsilon\)摩尔吸光系数molar absorption coefficientL·mol⁻¹·cm⁻¹
\(b\)光程path lengthcm
\(c\)浓度concentrationmol·L⁻¹

推导Derivation

  1. 厚 dx 的薄层吸收的光强与入射光强和吸光分子数成正比:\(-dI = k\,c\,I\,dx\)。

    A thin layer dx absorbs in proportion to intensity and absorber concentration: \(-dI = kcI\,dx\).

  2. 分离变量积分:\(\ln(I_0/I) = kcb\)。

    Integrate: \(\ln(I_0/I) = kcb\).

  3. 改用常用对数并令 \(\varepsilon = k/2.303\):\(A = \lg(I_0/I) = \varepsilon bc\)。

    Switch to log₁₀ with \(\varepsilon = k/2.303\).

  4. 微观上 ε 与分子吸收截面 σ 成正比:\(\sigma/\mathrm{cm^2} = 3.82\times10^{-21}\,\varepsilon/(\mathrm{L\,mol^{-1}\,cm^{-1}})\)。

    Microscopically ε is proportional to the absorption cross-section: \(\sigma/\mathrm{cm^2} = 3.82\times10^{-21}\,\varepsilon/(\mathrm{L\,mol^{-1}\,cm^{-1}})\).

适用条件与局限Assumptions & limitations

  • 适用于稀溶液(通常 c < 0.01 mol/L);高浓度时分子相互作用、折射率改变导致偏离。

    Dilute solutions (usually < 0.01 M); high concentration causes deviations.

  • 要求单色光;多色光、杂散光使校准曲线在高吸光度时弯曲(A 一般控制在 0.2–0.8 误差最小)。

    Requires monochromatic light; polychromatic or stray light bends curves at high A (best range 0.2–0.8).

  • 化学偏离:缔合、解离、酸碱平衡随浓度改变吸光物种。散射(浑浊样品)也会造成假吸收。

    Chemical deviations: association, dissociation, pH equilibria; scattering adds false absorbance.

例题Worked example

KMnO₄ 在 525 nm ε = 2.4×10³ L/(mol·cm),1 cm 比色皿测得 A = 0.48:c = 0.48/2400 = 2.0×10⁻⁴ mol/L。

KMnO₄ at 525 nm (ε = 2400): A = 0.48 in 1 cm gives c = 2.0×10⁻⁴ M.