双语化学辞典Chem Lexicon
本科Undergraduate 化学热力学 Chemical thermodynamics

克拉珀龙方程Clapeyron equation

\[\frac{dp}{dT} = \frac{\Delta_\text{trs}H}{T\,\Delta_\text{trs}V}\]

含义Meaning

任意两相平衡线(相图上的相界线)的斜率(1834)。冰的熔化 ΔV < 0,所以加压使冰的熔点降低——水是少数固液线斜率为负的物质。

The slope of any two-phase coexistence line (1834). Ice melts with ΔV < 0, so pressure lowers its melting point — water is one of few substances with a negative solid–liquid slope.

符号说明Symbols

符号Symbol含义 Meaning单位 Unit
\(\Delta_\text{trs}V\)相变体积变化volume change on transitionm³·mol⁻¹

推导Derivation

  1. 两相共存时 \(\mu_\alpha(T,p) = \mu_\beta(T,p)\);沿相界线移动 \(d\mu_\alpha = d\mu_\beta\)。

    Along the coexistence line dμ_α = dμ_β.

  2. \(-S_\alpha dT + V_\alpha dp = -S_\beta dT + V_\beta dp\),得 \(dp/dT = \Delta S/\Delta V\)。

    Hence dp/dT = ΔS/ΔV.

  3. 代入 \(\Delta S = \Delta H/T\)。

    Substitute ΔS = ΔH/T.

适用条件与局限Assumptions & limitations

  • 严格成立(无近似);积分时需知 ΔH、ΔV 随温度、压强的变化。

    Exact; integration needs ΔH and ΔV.

例题Worked example

冰:ΔfusH = 6.01 kJ/mol,ΔV = −1.63 cm³/mol:dp/dT = 6010/(273×(−1.63×10⁻⁶)) = −1.35×10⁷ Pa/K,即加压约 135 bar 熔点降低 1 K。

Ice: dp/dT ≈ −135 bar/K.