双语化学辞典Chem Lexicon
本科Undergraduate 化学热力学 Chemical thermodynamics

热力学第三定律与规定熵Third law and absolute entropy

\[\lim_{T\to0}S = 0\ (\text{完美晶体}),\qquad S(T) = \int_0^T\frac{C_p}{T}dT + \sum\frac{\Delta_\text{trs}H}{T_\text{trs}},\qquad C_p \approx aT^3\ (\text{德拜外推})\]\[\lim_{T\to0}S = 0\ (\text{perfect crystal}),\qquad S(T) = \int_0^T\frac{C_p}{T}dT + \sum\frac{\Delta_\text{trs}H}{T_\text{trs}},\qquad C_p \approx aT^3\ (\text{Debye extrapolation})\]

含义Meaning

能斯特热定理(1906)与普朗克表述:完美晶体在绝对零度熵为零。由此可通过量热测定物质的“绝对”(规定)熵,列成标准摩尔熵表。

The Nernst heat theorem (1906) and Planck’s statement: a perfect crystal has zero entropy at 0 K. Calorimetry then gives absolute (third-law) entropies tabulated as standard molar entropies.

符号说明Symbols

符号Symbol含义 Meaning单位 Unit
\(S_m^\circ\)标准摩尔熵standard molar entropyJ·mol⁻¹·K⁻¹

推导Derivation

  1. 完美晶体在 0 K 只有一个微观状态(W = 1),由 S = k ln W 得 S = 0。

    A perfect crystal at 0 K has W = 1.

  2. 从 0 K 起逐段积分 Cp/T 并加上各相变熵;最低温区用德拜 T³ 律外推。

    Integrate Cp/T from 0 K, adding transition entropies; extrapolate with T³ at the lowest temperatures.

  3. 推论:绝对零度不可能通过有限步骤达到。

    Corollary: absolute zero is unattainable in finitely many steps.

适用条件与局限Assumptions & limitations

  • 取向无序的晶体(CO、N₂O、冰)在 0 K 仍有残余熵。

    Orientationally disordered crystals (CO, N₂O, ice) keep residual entropy.

例题Worked example

298 K 标准摩尔熵:金刚石 2.4,石墨 5.7,H₂O(l) 70.0,H₂O(g) 188.8 J/(mol·K)。

S°(298 K): diamond 2.4, graphite 5.7, liquid water 70.0, steam 188.8 J mol⁻¹ K⁻¹.