双语化学辞典Chem Lexicon
概念 · 化学键 · 分子结构 Chemical bonding · Molecular structure

四面体形Tetrahedral molecular geometry

高中High school
拼音Pinyin sì miàn tǐ xíng 别名Also 正四面体形;四面体构型; tetrahedral

定义Definition

四面体形是中心原子与四个原子相连、四个原子位于四面体顶点的分子构型。当四个原子相同时为正四面体,键角为 109.5°(精确值 109°28′),如 CH₄、CCl₄、NH₄⁺。

Tetrahedral geometry is the molecular shape in which a central atom is bonded to four atoms at the corners of a tetrahedron. When all four are identical it is a regular tetrahedron with bond angles of 109.5° (exactly 109°28′), as in CH₄, CCl₄ and NH₄⁺.

成因Why the shape forms

中心原子周围有四个成键电子对、没有孤对电子时,四对电子相互排斥,在三维空间中距离最远的排列就是四面体,键角 109.5°,而不是平面正方形的 90°。用杂化轨道理论描述,中心原子为 sp³ 杂化。

With four bonding pairs and no lone pairs on the central atom, the arrangement that keeps the four pairs furthest apart in three dimensions is a tetrahedron, at 109.5°, not a square plane at 90°. In hybridisation terms the central atom is sp³.

例子Examples

分子:CH₄、CCl₄、SiH₄、SiCl₄。离子:NH₄⁺、BF₄⁻、SO₄²⁻、PO₄³⁻、MnO₄⁻、[CoCl₄]²⁻、[CuCl₄]²⁻(在许多盐中略有变形)。巨型结构:金刚石和二氧化硅中每个 C 或 Si 都处于四面体中心。

Molecules: CH₄, CCl₄, SiH₄, SiCl₄. Ions: NH₄⁺, BF₄⁻, SO₄²⁻, PO₄³⁻, MnO₄⁻, [CoCl₄]²⁻ and [CuCl₄]²⁻ (slightly distorted in many salts). Giant structures: each C in diamond and each Si in silicon dioxide sits at the centre of a tetrahedron.

与相关构型的比较Related shapes

四个电子对区域中有孤对电子时,电子对仍呈四面体排布,但分子构型改变:一对孤对为三角锥形(NH₃,107°),两对孤对为 V 形(H₂O,104.5°)。四个取代基不同的四面体碳原子没有对称面,是手性中心,存在对映异构体。

When some of the four regions are lone pairs, the electron pairs are still tetrahedral but the molecular shape changes: one lone pair gives trigonal pyramidal (NH₃, 107°), two give bent (H₂O, 104.5°). A tetrahedral carbon with four different groups has no mirror plane, is a chiral centre and has enantiomers.

年表Timeline

  • 1874

    范特霍夫与勒贝尔各自提出碳原子的四面体结构,解释旋光异构

    van 't Hoff and Le Bel independently propose the tetrahedral carbon atom to explain optical isomerism

  • 1913

    布拉格父子用 X 射线衍射证实金刚石中的四面体碳

    The Braggs confirm tetrahedral carbon in diamond by X-ray diffraction

相关公式Formulas

四面体分裂能与 CFSE Tetrahedral splitting and CFSE→
\[\Delta_\mathrm{t} \approx \frac49\Delta_\mathrm{o},\qquad \mathrm{CFSE}_\mathrm{t} = \left(-0.6\,n_e + 0.4\,n_{t_2}\right)\Delta_\mathrm{t}\]