双语化学辞典Chem Lexicon
研究生Graduate 化学动力学 Chemical kinetics

艾林方程(过渡态理论)Eyring equation (transition-state theory)

\[k = \kappa\frac{k_\mathrm BT}{h}\,e^{-\Delta^\ddagger G^\circ/RT} = \kappa\frac{k_\mathrm BT}{h}\,e^{\Delta^\ddagger S^\circ/R}\,e^{-\Delta^\ddagger H^\circ/RT}\]
艾林作图Eyring plot
\[\ln\frac kT = -\frac{\Delta^\ddagger H^\circ}{R}\cdot\frac1T + \ln\frac{k_\mathrm B}{h} + \frac{\Delta^\ddagger S^\circ}{R}\]
与阿伦尼乌斯活化能的关系relation to Arrhenius Ea
\[E_a = \Delta^\ddagger H^\circ + RT\ (\text{溶液中单分子})\]\[E_a = \Delta^\ddagger H^\circ + RT\ (\text{unimolecular in solution})\]

含义Meaning

艾林、埃文斯和波拉尼(1935)假设反应物与活化络合物(过渡态)处于准平衡,过渡态以频率 kT/h 越过势垒。由此可从速率常数的温度依赖得到活化焓和活化熵。

Eyring, Evans and Polanyi (1935) assumed quasi-equilibrium between reactants and the activated complex, which crosses the barrier at frequency kT/h. Temperature dependence then yields activation enthalpy and entropy.

符号说明Symbols

符号Symbol含义 Meaning单位 Unit
\(\Delta^\ddagger G^\circ\)活化吉布斯能Gibbs energy of activationkJ·mol⁻¹
\(\Delta^\ddagger H^\circ, \Delta^\ddagger S^\circ\)活化焓、活化熵enthalpy and entropy of activationkJ·mol⁻¹, J·mol⁻¹·K⁻¹
\(\kappa\)透射系数(通常取 1)transmission coefficient (usually 1)1
\(k_\mathrm BT/h\)普适频率(298 K 时 6.2×10¹² s⁻¹)universal frequency (6.2×10¹² s⁻¹ at 298 K)s⁻¹

推导Derivation

  1. A + B ⇌ [AB]‡ → P,\(K^\ddagger = [\mathrm{AB}^\ddagger]/([\mathrm A][\mathrm B])\)。

    Assume A + B ⇌ [AB]‡ in quasi-equilibrium.

  2. 沿反应坐标的那个振动频率 ν 很低,把它从 \(K^\ddagger\) 的配分函数中分离出来得 \(k_\mathrm BT/h\nu\)。

    Factor the low reaction-coordinate vibration out of the partition function, giving \(k_\mathrm BT/h\nu\).

  3. 速率 = ν[AB‡],ν 相消:\(k = (k_\mathrm BT/h)\bar K^\ddagger\)。

    Rate = ν[AB‡]; ν cancels.

  4. 用 \(\Delta^\ddagger G^\circ = -RT\ln\bar K^\ddagger\) 得艾林方程。

    Use \(\Delta^\ddagger G^\circ = -RT\ln\bar K^\ddagger\).

适用条件与局限Assumptions & limitations

  • 假设越过过渡态后不返回(κ ≈ 1);隧穿(轻原子转移)和溶剂动力学效应需修正。

    Assumes no recrossing; tunnelling and solvent dynamics need corrections.

  • 活化熵符号可提示机理:缔合型 ΔS‡ < 0,解离型 ΔS‡ > 0。

    The sign of ΔS‡ hints at associative (<0) or dissociative (>0) mechanisms.

例题Worked example

室温下 ΔG‡ = 80 kJ/mol 对应 k = 6.2×10¹²×e^(−80000/2478) ≈ 0.06 s⁻¹(t½ ≈ 11 s);每增加 5.7 kJ/mol 速率降为 1/10。

At room temperature ΔG‡ = 80 kJ/mol gives k ≈ 0.06 s⁻¹; each 5.7 kJ/mol slows it tenfold.