双语化学辞典Chem Lexicon
高中Senior high 化学计量与基本定律 Stoichiometry & basic laws

物质的量浓度Molar concentration (molarity)

\[c_{\mathrm{B}} = \frac{n_{\mathrm{B}}}{V}\]

含义Meaning

单位体积溶液中所含溶质的物质的量,单位 mol/L。

Amount of solute per unit volume of solution, in mol/L.

符号说明Symbols

符号Symbol含义 Meaning单位 Unit
\(c_\mathrm{B}\)溶质 B 的物质的量浓度molar concentration of solute Bmol·L⁻¹
\(n_\mathrm{B}\)溶质的物质的量amount of solutemol
\(V\)溶液体积(不是溶剂体积)volume of solution (not of solvent)L

推导Derivation

  1. 按定义:溶质物质的量除以溶液体积。

    By definition: amount of solute divided by solution volume.

  2. 配制溶液时先求 \(n = cV\),再由 \(m = nM\) 称量,定容到容量瓶刻度。

    To prepare a solution compute \(n = cV\), weigh \(m = nM\), and make up to the mark in a volumetric flask.

  3. 离子浓度按化学式计量:0.1 mol/L Na₂SO₄ 中 c(Na⁺) = 0.2 mol/L。

    Ion concentrations follow the formula: 0.1 mol/L Na₂SO₄ has c(Na⁺) = 0.2 mol/L.

适用条件与局限Assumptions & limitations

  • V 是溶液体积,随温度变化,所以 c 随温度略变(水约 0.02%/K);精密工作用质量摩尔浓度 b。

    V is the solution volume and changes with temperature, so c drifts slightly (~0.02 %/K for water); precise work uses molality b.

  • 弱电解质部分电离、强电解质高浓度下离子缔合,实际“有效浓度”需用活度表示。

    Partial dissociation and ion pairing mean the effective concentration is the activity, not c.

例题Worked example

把 5.85 g NaCl 溶于水配成 250 mL 溶液:n = 0.100 mol,c = 0.100/0.250 = 0.400 mol/L。

5.85 g NaCl made up to 250 mL: n = 0.100 mol, c = 0.400 mol/L.